定积分存在性的两道题① 对于分段函数f(x)=sin(1/x),x≠0;f(x)=0,x=0.书上说该函数是有界函数所以在闭区间[-2,2]存在定积分,可是仔细想想当x->0时sin(1/x)虽然有界但在这个无限趋于零的过程中你
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![定积分存在性的两道题① 对于分段函数f(x)=sin(1/x),x≠0;f(x)=0,x=0.书上说该函数是有界函数所以在闭区间[-2,2]存在定积分,可是仔细想想当x->0时sin(1/x)虽然有界但在这个无限趋于零的过程中你](/uploads/image/z/14288623-7-3.jpg?t=%E5%AE%9A%E7%A7%AF%E5%88%86%E5%AD%98%E5%9C%A8%E6%80%A7%E7%9A%84%E4%B8%A4%E9%81%93%E9%A2%98%E2%91%A0+%E5%AF%B9%E4%BA%8E%E5%88%86%E6%AE%B5%E5%87%BD%E6%95%B0f%28x%29%3Dsin%281%2Fx%29%2Cx%E2%89%A00%EF%BC%9Bf%28x%29%3D0%2Cx%3D0.%E4%B9%A6%E4%B8%8A%E8%AF%B4%E8%AF%A5%E5%87%BD%E6%95%B0%E6%98%AF%E6%9C%89%E7%95%8C%E5%87%BD%E6%95%B0%E6%89%80%E4%BB%A5%E5%9C%A8%E9%97%AD%E5%8C%BA%E9%97%B4%5B-2%2C2%5D%E5%AD%98%E5%9C%A8%E5%AE%9A%E7%A7%AF%E5%88%86%2C%E5%8F%AF%E6%98%AF%E4%BB%94%E7%BB%86%E6%83%B3%E6%83%B3%E5%BD%93x-%3E0%E6%97%B6sin%281%2Fx%29%E8%99%BD%E7%84%B6%E6%9C%89%E7%95%8C%E4%BD%86%E5%9C%A8%E8%BF%99%E4%B8%AA%E6%97%A0%E9%99%90%E8%B6%8B%E4%BA%8E%E9%9B%B6%E7%9A%84%E8%BF%87%E7%A8%8B%E4%B8%AD%E4%BD%A0)
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