求极限(sin (x -π/3))/(1-2cos x ) x
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 11:41:28
x){ټƗ3'Q *t7kjk%+T(h*T$铢\Άd\b[v=];H>[y/Dɮ>SV<2=<(Q=OvQkb\
mO7U<ٽiҧnlNc+_,\|ɮgݽt$ف (k&
求极限(sin (x -π/3))/(1-2cos x ) x
求极限(sin (x -π/3))/(1-2cos x ) x
求极限(sin (x -π/3))/(1-2cos x ) x
当x趋近3 分子分母都趋近于0 则用洛必达法则,分子求导为cos(x-?/3)分母求导为2sinx,再将x=?/3代入可得1/根3(?表示拍)
求极限 sin(x-π/3)/1-cosx 在x趋向π/2的极限
求极限(sin (x -π/3))/(1-2cos x ) x
求极限lim趋近于1 sin(πx^a)/sin(πx^b)的值
求极限 ((sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1
求极限:sin x^tan x(x→π/2)
求极限:sin x^tan x(x→π)
求极限,lim x趋于0 x * sin 1/x
求x*sin[2x/(x^2+1)]的极限
求极限lim(x-->0)x^2 sin(1/x),
求x趋于2,3,4,n时(x-x^3)/sinπx的极限,
求极限 x趋向于π/3 ((1-2cosx)ln(1+x))/sin(x-π/3)
求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0
求三道三角极限题的解法1,x趋近π,求[1+sin(x-3/2π)]/(x-π)的极限2,x趋近π/4,求(x-π/4)²/(tanx-1)²的极限3,x趋近3,求[x-sin(x-3)-3]/(x-3)的极限写详细点谢谢
limx->1 sin(x-1)/x-1 求极限
sin(-x)/1-根号下1-x,求极限,
求极限lim(x-->0) (tanX-sinX)/[(sin^3)X]
求极限:lim(x*sin(1/x))^2
lim x->0(sqrt(sin(1/x^2)) 求极限