(2xy-y)-(-y+xy)去括号并合并同类项

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(2xy-y)-(-y+xy)去括号并合并同类项
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(2xy-y)-(-y+xy)去括号并合并同类项
(2xy-y)-(-y+xy)去括号并合并同类项

(2xy-y)-(-y+xy)去括号并合并同类项
(2xy-y)-(-y+xy)=2xy-y+y-xy=xy

xy

(2xy-y)-(-y+xy)
=xy

xy

(2xy-y)-(-y+xy)
原式=2xy-y+y-xy
=xy

(2xy-y)-(-y+xy)
原式=2xy-y+y-xy
=(2-1)xy+(-1+1)y
=xy
答案是等于xy。