1.已知f(x)=ax平方+bx是定义在[a-1,2a]上的偶函数,求a+b=2.设f(x)是定义在(0,正无穷)上的增函数,对a,b属于(0,正无穷)都有f(a/b)=f(a)-f(b)成立,且f(2)=1,求不等式f(x)-f[1/(x-2)]小于等于3的解集3.设f(x)是连续
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![1.已知f(x)=ax平方+bx是定义在[a-1,2a]上的偶函数,求a+b=2.设f(x)是定义在(0,正无穷)上的增函数,对a,b属于(0,正无穷)都有f(a/b)=f(a)-f(b)成立,且f(2)=1,求不等式f(x)-f[1/(x-2)]小于等于3的解集3.设f(x)是连续](/uploads/image/z/14312447-71-7.jpg?t=1.%E5%B7%B2%E7%9F%A5f%28x%29%3Dax%E5%B9%B3%E6%96%B9%2Bbx%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9C%A8%5Ba-1%2C2a%5D%E4%B8%8A%E7%9A%84%E5%81%B6%E5%87%BD%E6%95%B0%2C%E6%B1%82a%2Bb%3D2.%E8%AE%BEf%28x%29%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9C%A8%280%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%29%E4%B8%8A%E7%9A%84%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E5%AF%B9a%2Cb%E5%B1%9E%E4%BA%8E%280%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%29%E9%83%BD%E6%9C%89f%28a%2Fb%29%3Df%28a%29-f%28b%29%E6%88%90%E7%AB%8B%2C%E4%B8%94f%282%29%3D1%2C%E6%B1%82%E4%B8%8D%E7%AD%89%E5%BC%8Ff%28x%29-f%5B1%2F%28x-2%29%5D%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E3%E7%9A%84%E8%A7%A3%E9%9B%863.%E8%AE%BEf%28x%29%E6%98%AF%E8%BF%9E%E7%BB%AD)
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