(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 18:35:28
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
x)067҄Pqp aci$铨CΆ[{: urtn q4!UꀢyLic#k ~qAb(tKvx

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
原式=2×(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
=2×(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
=2×(1-1/2^4)(1+1/2^4)(1+1/2^8)(1+1/2^16),
=2×(1-1/2^8)(1+1/2^8)(1+1/2^16),
=2×(1-1/2^16)(1+1/2^16)
=2×(1-1/2^32)
=(2^32-1)/2^31