CI2的制法,①MnO2+4HCI(浓)=MnCI2+CI2+2H2O②KMnO4+16HCI(浓)=2KCI+2MnCI2+5CI2+8H2O③ Ca(CIO)2+4HCI(浓)=CaCI2+2CI2+2H2O④KCIO3+6HCI(浓)=KCI+3CI2+3H2O这四个反应是制取CI2的反应,我把反映条件和气标省去了,不
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![CI2的制法,①MnO2+4HCI(浓)=MnCI2+CI2+2H2O②KMnO4+16HCI(浓)=2KCI+2MnCI2+5CI2+8H2O③ Ca(CIO)2+4HCI(浓)=CaCI2+2CI2+2H2O④KCIO3+6HCI(浓)=KCI+3CI2+3H2O这四个反应是制取CI2的反应,我把反映条件和气标省去了,不](/uploads/image/z/14335137-9-7.jpg?t=CI2%E7%9A%84%E5%88%B6%E6%B3%95%2C%E2%91%A0MnO2%2B4HCI%EF%BC%88%E6%B5%93%EF%BC%89%3DMnCI2%2BCI2%2B2H2O%E2%91%A1KMnO4%2B16HCI%EF%BC%88%E6%B5%93%EF%BC%89%3D2KCI%2B2MnCI2%2B5CI2%2B8H2O%E2%91%A2+Ca%EF%BC%88CIO%292%2B4HCI%EF%BC%88%E6%B5%93%EF%BC%89%3DCaCI2%2B2CI2%2B2H2O%E2%91%A3KCIO3%2B6HCI%28%E6%B5%93%EF%BC%89%3DKCI%2B3CI2%2B3H2O%E8%BF%99%E5%9B%9B%E4%B8%AA%E5%8F%8D%E5%BA%94%E6%98%AF%E5%88%B6%E5%8F%96CI2%E7%9A%84%E5%8F%8D%E5%BA%94%2C%E6%88%91%E6%8A%8A%E5%8F%8D%E6%98%A0%E6%9D%A1%E4%BB%B6%E5%92%8C%E6%B0%94%E6%A0%87%E7%9C%81%E5%8E%BB%E4%BA%86%2C%E4%B8%8D)
CI2的制法,①MnO2+4HCI(浓)=MnCI2+CI2+2H2O②KMnO4+16HCI(浓)=2KCI+2MnCI2+5CI2+8H2O③ Ca(CIO)2+4HCI(浓)=CaCI2+2CI2+2H2O④KCIO3+6HCI(浓)=KCI+3CI2+3H2O这四个反应是制取CI2的反应,我把反映条件和气标省去了,不
CI2的制法,
①MnO2+4HCI(浓)=MnCI2+CI2+2H2O
②KMnO4+16HCI(浓)=2KCI+2MnCI2+5CI2+8H2O
③ Ca(CIO)2+4HCI(浓)=CaCI2+2CI2+2H2O
④KCIO3+6HCI(浓)=KCI+3CI2+3H2O
这四个反应是制取CI2的反应,我把反映条件和气标省去了,不妨碍的.
书上说HCI作为还原剂,部分(依次是2/4,10/16,2/4,5/6)被氧化成CI2
这里的部分(依次是2/4,10/16,2/4,5/6)里面的数字什么意思啊,怎么看出来的?
CI2的制法,①MnO2+4HCI(浓)=MnCI2+CI2+2H2O②KMnO4+16HCI(浓)=2KCI+2MnCI2+5CI2+8H2O③ Ca(CIO)2+4HCI(浓)=CaCI2+2CI2+2H2O④KCIO3+6HCI(浓)=KCI+3CI2+3H2O这四个反应是制取CI2的反应,我把反映条件和气标省去了,不
数字为消耗的HCl与生成的Cl2的比值~
反应一为2/4,是因为消耗4molHCL生成1molCl2,所以4mol中有2mol变成Cl2即为2/4
同理~可知反应二为10/16
反应三为归中反应,所以Ca(CIO)2中Cl变为Cl2(1mol),而2molHCl中有1mol变成Cl2所以为2/4
同理~可知反应四为5/6