#include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k+m); printf("%d",a);}

#define s(x) 3 #define S(x) 3 3．设有以下程序：、#include #define S(X) X*Xvoid main(void){int k=2；cout #include #define S(x) x*x main() {int a=9,k=3,m=2; a/=S(k+m)/S(k+m); print(%d,a); #include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k+m); printf(%d,a);} 一道数据结构题：#include #include #define STACK_INIT_SIZE 100#define STACKINCREMENT 10#define OK 1#define ERROR 0typedef struct{int *base;int *top;int stacksize;}SqStack;int InitStack(SqStack *S){S->base=(int *)malloc(STACK_INIT_SIZE*sizeof(i 求此程序的解释,就是#define s(x) 4*(x)*x+1这语句是什么意思啊,怎么运算#include#define s(x) 4*(x)*x+1main(){int k=5, j=2;printf(%d ,s(k+j));} 这俩题的答案是几,怎么算的?第一题：#define N 3#define Y（n） （（N+1）*n）则执行语句：z=2*（N+Y（5+1));后,z的值为——第二题：#include #define PT 5.5#define S(X) PT*X*Xvoid main(){int a=1,b=2;printf(%4.1f/n,S(a #include#include#define MAXNUM 20struct stacktype{int stack[MAXNUM];int top;};void InitStack(struct stacktype *s){s->top=-1;}int StackEmpty(struct stacktype *s){return(s->top==0);}int push(struct stacktype *s,int x){ if(s->top >= MAXNUM-1)return fals matlab中的S-函数问题永磁无刷直流电机,对于S-函数的实现,使用C MEX S-函数执行#define S_FUNCTION_NAME chengxu#define S_FUNCTION_LEVEL 2#include "simstruc.h"#include "math.h"`static void mdlInitializeSizes(S #include #include #include #include #include /* define请大家帮我修改下! #include #include #define TRUE 1 #define FALSE 0 #define OK 1 #define ERROR 0 #d能不能帮改下程序 #include #define A 2 #define B(x) x*(A+2) void main() { int a=5; printf(%d ,B(a+1)); } #include #define N 10 int i,j,s,z; int a[N],a[N][N],b[N-1],c[N-1],t[N][N],m[N][N],x[N] 自己完全不懂!#define PI 3.1415#include #include void main(){float x,y,PI;printf(please input x:);scanf(%f,&x);if(x 括号匹配问题,出错在哪!#include#include#include#define OK 1#define ERROR -1#define OVERFLOW -2typedef struct{char *base;char *top;char stacksize;}SqStack;int InitStack(SqStack &s){s.base=(char *)malloc(100*sizeof(char));if(!s.base)exit(OVERF #include #define X 5 #define Y X+1 #define Z Y*X/2 main() { int a; a=Y; printf(%d %d ,Z结果为什么是7 5呢,不解, #includestdio.h #define F(y) 3.84+y #define PR(a) printf(%d,(int)(a)) main(){ int x=3; PR(F(3)*#includestdio.h#define F(y) 3.84+y#define PR(a) printf(%d,(int)(a))main(){int x=3;PR(F(3)*x); }为什么结果是12啊?