1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两
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![1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两](/uploads/image/z/144299-11-9.jpg?t=1.3.5.7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B71991.1993.1995.1997.1999%E5%92%8C1.4.7.10%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B71990.1993.1996.1999%E5%90%8C%E6%97%B6%E5%87%BA%E7%8E%B0%E5%9C%A8%E8%BF%99%E4%B8%A4)
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1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两
1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两
1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两
1.3.5.7······这个数列是后数 = 前数 + 2
1.4.7.10·····这个数列是后数 = 前数 + 3
2、3的最小公倍数为6
因此从第一项开始,每 + 6,数字重复.
(1999 - 1)/6 = 333
因此从1、7、13到 1 + 333*6 = 1999
一共有 333 + 1 = 334 个数字同时出现在两个数列.
单数(1.3.5.7.9······)阶幻方怎么做?
1.3.5.7······1991.1993.1995.1997.1999和1.4.7.10······1990.1993.1996.1999同时出现在这两
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