如图点efgh分别在菱形abcd的四条边上,且BE=BF=DG=DH,连接EF,FG,GH,HE得到四边形EFGH.(1)求证:四边形EFGH是矩形;(2)设AB=a,∠A=60°,当BE为何值时,矩形EFGH的面积最大第二问的要求:设AE=x,则BE=a-x,
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![如图点efgh分别在菱形abcd的四条边上,且BE=BF=DG=DH,连接EF,FG,GH,HE得到四边形EFGH.(1)求证:四边形EFGH是矩形;(2)设AB=a,∠A=60°,当BE为何值时,矩形EFGH的面积最大第二问的要求:设AE=x,则BE=a-x,](/uploads/image/z/14524161-33-1.jpg?t=%E5%A6%82%E5%9B%BE%E7%82%B9efgh%E5%88%86%E5%88%AB%E5%9C%A8%E8%8F%B1%E5%BD%A2abcd%E7%9A%84%E5%9B%9B%E6%9D%A1%E8%BE%B9%E4%B8%8A%2C%E4%B8%94BE%3DBF%3DDG%3DDH%2C%E8%BF%9E%E6%8E%A5EF%2CFG%2CGH%2CHE%E5%BE%97%E5%88%B0%E5%9B%9B%E8%BE%B9%E5%BD%A2EFGH.%281%29%E6%B1%82%E8%AF%81%3A%E5%9B%9B%E8%BE%B9%E5%BD%A2EFGH%E6%98%AF%E7%9F%A9%E5%BD%A2%3B%282%29%E8%AE%BEAB%3Da%2C%E2%88%A0A%3D60%C2%B0%2C%E5%BD%93BE%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6%2C%E7%9F%A9%E5%BD%A2EFGH%E7%9A%84%E9%9D%A2%E7%A7%AF%E6%9C%80%E5%A4%A7%E7%AC%AC%E4%BA%8C%E9%97%AE%E7%9A%84%E8%A6%81%E6%B1%82%EF%BC%9A%E8%AE%BEAE%3Dx%EF%BC%8C%E5%88%99BE%3Da-x%EF%BC%8C)
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