梯形ABCD中,AB平行CD,AB⊥BC,∠B=45°,AB=BC,直线MC平行AD,点E在直线CD上,EF⊥AE交CM与F,求证求证AD-CF=√2DE
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![梯形ABCD中,AB平行CD,AB⊥BC,∠B=45°,AB=BC,直线MC平行AD,点E在直线CD上,EF⊥AE交CM与F,求证求证AD-CF=√2DE](/uploads/image/z/14531913-9-3.jpg?t=%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%E5%B9%B3%E8%A1%8CCD%2CAB%E2%8A%A5BC%2C%E2%88%A0B%3D45%C2%B0%2CAB%3DBC%2C%E7%9B%B4%E7%BA%BFMC%E5%B9%B3%E8%A1%8CAD%2C%E7%82%B9E%E5%9C%A8%E7%9B%B4%E7%BA%BFCD%E4%B8%8A%2CEF%E2%8A%A5AE%E4%BA%A4CM%E4%B8%8EF%2C%E6%B1%82%E8%AF%81%E6%B1%82%E8%AF%81AD-CF%3D%E2%88%9A2DE)
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