f(n)=1/(n+1)+1/(n+2)+1/(n+3)+……+1/(2n),(n∈N+),f(k+1)-f(k)=重要的是过程……
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 20:34:26
x)KӴ56FPXSQ2 q4u4utiө
T4m_X|V˳_o&H
ƃi~
<R HC ,Tk5!TX&(AP0CЍ +i';طiGӎgxޏ,lب F 1\
f(n)=1/(n+1)+1/(n+2)+1/(n+3)+……+1/(2n),(n∈N+),f(k+1)-f(k)=重要的是过程……
f(n)=1/(n+1)+1/(n+2)+1/(n+3)+……+1/(2n),(n∈N+),f(k+1)-f(k)=
重要的是过程……
f(n)=1/(n+1)+1/(n+2)+1/(n+3)+……+1/(2n),(n∈N+),f(k+1)-f(k)=重要的是过程……
f(k+1)=1/(k+1+1)+1/(k+1+2)+1/(k+1+3)+……+1/(2k)+1/(2k+1)+1/(2(k+1))
f(k)=1/(k+1)+1/(k+2)+1/(k+3)+……+1/(2k)
等号两边分别相减
f(k+1)-f(k) = 1/(2k+1)+1/(2(k+1)) - 1/(k+1)
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
f(1)+f(2)+f(3)+...+f(n)=n/n+1.求f(n)
设f(n)=1+2+3+.n,则(n-->+∞)limf(n)/[f(n)]=
设f(n)=1/n+1+1/n+2+1/n+3+……+1/3n(n∈N+),则f(n+1)-f(n)=?
f(n+1)>f(n),f(f(n))=3n.n属于正整数.令an=f(3*n次方),证明n/4n+2
已知n属于N,n>=1,f(n)=√(n^2+1)-n,t(n)=1/2n,g(n)=n-√(n^2-1)则f(n),t(n),g(n)的大小关系为?
f(n)=(n+1/n)^n 求导
f(n)=1/n+1+1/n+2+/1n+3+.+1/2n(n包涵正整数那么f(n+1)-f(n)=
设f(n)=1/n+1+1/n+2+…+1/2n(n属于N*),那么f(n+1)-f(n)=
如果f(n)=1/(n+1)+1/(n+2)+```1/2n (n属于N*) 那么f(n+1)-f(n)=
F(n+1)^2+F(n)2
f(n)= -n+√(n^2+1) h(n)=1/2n g(n)=n-√(n^2-1) 比较大小n为自然数
求证f(n+1)*f(n-1)-f(n)*f(n) = (-1)^n,f(n)是费波纳茨数列
f(X+1)=lim(n-无穷)(n+x)/n-2)n 求f(x)
f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1)-f(n)=?
若f(n)=[1/(n+1)]+[1/(n+2)]+[1/(n+3)]+``` ```+(1/2n),则f(n+1)-f(n)=
f(1)=2,f(n+1)=[2f(n)+6]/f(n)=1,求f(n)
f(n+1)=2f(n)/f(n)+2,f(1)=1,猜想f(n)的表达式