初一数学...么么哒...↖(^ω^)↗
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 01:38:12
![初一数学...么么哒...↖(^ω^)↗](/uploads/image/z/14559033-57-3.jpg?t=%E5%88%9D%E4%B8%80%E6%95%B0%E5%AD%A6...%E4%B9%88%E4%B9%88%E5%93%92...%E2%86%96%28%5E%CF%89%5E%29%E2%86%97)
xN@_E9X=`)4l
:J$VBbX;P6kC$EH|33a3N_.w<ϛ=agWa|V;*CT",גC]UQzU'IGrˋ2"%##/R=Du+1^_QU"L!Fԉ6BBeF$S Q_d,&S`i(kJ4OSͼd+e"Y" `L2ųqL^1WJ/t}llD^&Y4}5֥Dv1zb1Cm0n7S#W9q;|HH q`-;wj67oL*DUF@e#90}/`}j2`l
初一数学...么么哒...↖(^ω^)↗
初一数学...么么哒...↖(^ω^)↗
初一数学...么么哒...↖(^ω^)↗
因3x^2-x=1所3x^2=x+1
所6x^3+7x^2-5x+2006
=x(6x^2+7x-5)+2006
=x(2x-1)(3x+5)+2006
=(2x-1)(3x^2+5x)+2006
=(2x-1)(1+x+5x)+2006
=(2x-1)(6x+1)+2006
=12x^2-4x-1+2006
=4(3x^2-x)+2005
=4*1+2005
=2009
因为3x^2-x=1,所以3x^2=x+1
所以6x^3+7x^2-5x+2006
=x(6x^2+7x-5)+2006
=x(2x-1)(3x+5)+2006
=(2x-1)(3x^2+5x)+2006
=(2x-1)(1+x+5x)+2006
=(2x-1)(6x+1)+2006
=12x^2-4x-1+2006
=4(3x^2-x)+2005
=4*1+2005
=2009