作业帮初二二次根式 化简求值
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初二二次根式 化简求值
初二二次根式 化简求值 
初二二次根式 化简求值
(x²+2xy+y²)/(x²-y²)÷(x²+xy)/(x-y)
=(x+y)²/(x²-y²)÷(x²+xy)/(x-y)
=(x+y)/(x-y)×(x-y)/(x²+xy)
=(x+y)/(x²+xy)
=(x+y)/[x(x+y)]
=1/x
=1/(√2-1)
=√2+1.