求证m取任何值时,直线l:(2m+1)x+(m+1)y-7m-4=0与 圆C:(x-1)^2+(y-2)^2=25 恒交于两点为何能想到将直线l与分解成2x+y-7=0x+y-4=0 的两个方程组备注:x^2表示x的平方
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![求证m取任何值时,直线l:(2m+1)x+(m+1)y-7m-4=0与 圆C:(x-1)^2+(y-2)^2=25 恒交于两点为何能想到将直线l与分解成2x+y-7=0x+y-4=0 的两个方程组备注:x^2表示x的平方](/uploads/image/z/14600931-51-1.jpg?t=%E6%B1%82%E8%AF%81m%E5%8F%96%E4%BB%BB%E4%BD%95%E5%80%BC%E6%97%B6%2C%E7%9B%B4%E7%BA%BFl%3A%282m%2B1%29x%2B%28m%2B1%29y-7m-4%3D0%E4%B8%8E+%E5%9C%86C%3A%28x-1%29%5E2%2B%28y-2%29%5E2%3D25+%E6%81%92%E4%BA%A4%E4%BA%8E%E4%B8%A4%E7%82%B9%E4%B8%BA%E4%BD%95%E8%83%BD%E6%83%B3%E5%88%B0%E5%B0%86%E7%9B%B4%E7%BA%BFl%E4%B8%8E%E5%88%86%E8%A7%A3%E6%88%902x%2By-7%3D0x%2By-4%3D0+%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%96%B9%E7%A8%8B%E7%BB%84%E5%A4%87%E6%B3%A8%3Ax%5E2%E8%A1%A8%E7%A4%BAx%E7%9A%84%E5%B9%B3%E6%96%B9)
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