已知下列两个热化学方程式,解两小题H2(g)+1/2O2(g)=H2O(L); △H=-285.kJ/molC3H8(g)+5O2(g)=3CO2(g)+4H2O(1) △H=-2220.0kJ/mol(1)实验测得H2和C3H8的混合气体共5mol,完全燃烧生成液态水时放热6262.5kJ,则混合
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![已知下列两个热化学方程式,解两小题H2(g)+1/2O2(g)=H2O(L); △H=-285.kJ/molC3H8(g)+5O2(g)=3CO2(g)+4H2O(1) △H=-2220.0kJ/mol(1)实验测得H2和C3H8的混合气体共5mol,完全燃烧生成液态水时放热6262.5kJ,则混合](/uploads/image/z/14838701-5-1.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%8B%E5%88%97%E4%B8%A4%E4%B8%AA%E7%83%AD%E5%8C%96%E5%AD%A6%E6%96%B9%E7%A8%8B%E5%BC%8F%2C%E8%A7%A3%E4%B8%A4%E5%B0%8F%E9%A2%98H2%28g%29%2B1%2F2O2%28g%29%3DH2O%28L%29%EF%BC%9B+%E2%96%B3H%3D%EF%BC%8D285.kJ%2FmolC3H8%28g%29%2B5O2%28g%29%3D3CO2%28g%29%2B4H2O%281%29+%E2%96%B3H%3D%EF%BC%8D2220.0kJ%2Fmol%EF%BC%881%EF%BC%89%E5%AE%9E%E9%AA%8C%E6%B5%8B%E5%BE%97H2%E5%92%8CC3H8%E7%9A%84%E6%B7%B7%E5%90%88%E6%B0%94%E4%BD%93%E5%85%B15mol%2C%E5%AE%8C%E5%85%A8%E7%87%83%E7%83%A7%E7%94%9F%E6%88%90%E6%B6%B2%E6%80%81%E6%B0%B4%E6%97%B6%E6%94%BE%E7%83%AD6262.5kJ%2C%E5%88%99%E6%B7%B7%E5%90%88)
已知下列两个热化学方程式,解两小题H2(g)+1/2O2(g)=H2O(L); △H=-285.kJ/molC3H8(g)+5O2(g)=3CO2(g)+4H2O(1) △H=-2220.0kJ/mol(1)实验测得H2和C3H8的混合气体共5mol,完全燃烧生成液态水时放热6262.5kJ,则混合
已知下列两个热化学方程式,解两小题
H2(g)+1/2O2(g)=H2O(L); △H=-285.kJ/mol
C3H8(g)+5O2(g)=3CO2(g)+4H2O(1) △H=-2220.0kJ/mol
(1)实验测得H2和C3H8的混合气体共5mol,完全燃烧生成液态水时放热6262.5kJ,则混合气体中H2和C3H8的体积比是
(2)已知:H2O(1)=H2O(g);△H=+44.0kJ/mol 写出丙烷燃烧生成CO2和气态水的热化学方程式.
已知下列两个热化学方程式,解两小题H2(g)+1/2O2(g)=H2O(L); △H=-285.kJ/molC3H8(g)+5O2(g)=3CO2(g)+4H2O(1) △H=-2220.0kJ/mol(1)实验测得H2和C3H8的混合气体共5mol,完全燃烧生成液态水时放热6262.5kJ,则混合
(1)设氢气xmol,丙烷ymol,则可得x+y=5,且285x+2220y=6262.5,联立两方程解得,x=2.5mol,y=2.5mol,则混合气体中H2和C3H8的体积比是1:1..
(2)此过程只需考虑水的液体到气体的转换时的能量就可,因水的液体到气体需吸热44.0kJ/mol ,所以丙烷燃烧生成CO2和气态水的热化学方程式为C3H8(g)+5O2(g)=3CO2(g)+4H2O(g) △H=-2176.0kJ/mol.