FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入
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![FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入](/uploads/image/z/14965859-11-9.jpg?t=FatMouse%27+Trade%E6%9C%89N%E4%B8%AA%E6%88%BF%E9%97%B4%2C%E4%BD%A0%E6%9C%89M%E9%95%91%E7%9A%84%E7%8C%AB%E7%B2%AE%2C%E5%9C%A8%E7%AC%ACi%E4%B8%AA%E6%88%BF%E9%97%B4%E4%BD%A0%E6%9C%80%E5%A4%9A%E5%8F%AF%E4%BB%A5%E8%8A%B1%E8%B4%B9F%5Bi%5D%E7%9A%84%E7%8C%AB%E7%B2%AE%E6%9D%A5%E4%BA%A4%E6%8D%A2J%5Bi%5D%E7%9A%84%E8%B1%86%E5%AD%90%2C%E4%BA%A4%E6%8D%A2%E5%8F%AF%E4%BB%A5%E6%8C%89%E6%AF%94%E4%BE%8B%E6%9D%A5%2C%E4%B8%8D%E4%B8%80%E5%AE%9A%E5%85%A8%E9%83%A8%E4%BA%A4%E6%8D%A2%2C%E8%83%BD%E5%9C%A8%E5%A4%9A%E4%B8%AA%E6%88%BF%E9%97%B4%E4%BA%A4%E6%8D%A2.%E6%B1%82M%E9%95%91%E6%9C%80%E5%A4%9A%E8%83%BD%E4%BA%A4%E6%8D%A2%E5%A4%9A%E5%B0%91%E8%B1%86%E5%AD%90.%E8%BE%93%E5%85%A5%E6%8F%8F%E8%BF%B0%EF%BC%9A%E8%BE%93%E5%85%A5)
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FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入
FatMouse' Trade
有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.
输入描述:
输入数据有多组,每行有两个整数M和N,接下有N行,每行有两个整数J[i]和F[i].当M=-1和N=-1时结束.所有整数不会大于1000.
输出描述:
输出能还得最大最大豆子数,保留三位小数.
样例输入:
5 3
7 2
4 3
5 2
20 3
25 18
24 15
15 10
-1 -1
样例输出:
13.333
31.500
FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入
#include
struct
{
int java;
int food;
double aver;
}unit[10000],t;
int main()
{
int i,j,k,m,n;
double sum;
while(scanf("%d%d",&m,&n)!=EOF&&n!=-1&&m!=-1)
{
sum=0;
for(i=0;i
FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入
FatMouse' Trade有N个房间,你有M镑的猫粮,在第i个房间你最多可以花费F[i]的猫粮来交换J[i]的豆子,交换可以按比例来,不一定全部交换,能在多个房间交换.求M镑最多能交换多少豆子.输入描述:输入
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帮我看看这为什么在oj上就是不行 FatMouse' TradeDescriptionFatMouse prepared M pounds of cat food,ready to trade with the cats guarding the warehouse containing his favorite food,JavaBean.The warehouse has N rooms.The i-th room contains J
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C语言编程题 FatMouse' TradeFatMouse' TradeTime Limit:1000MS Memory Limit:65536KTotal Submit:395 Accepted:95 Description FatMouse prepared M pounds of cat food,ready to trade with the cats guarding the warehouse containing his favorite food,JavaB
杭电 oj FatMouse' Trade原题连接:代码太长,不能发,考虑到了catfood 可能为0的情况,但是还是一直wa给个代码的连接吧,http://hi.baidu.com/%E6%88%91%E6%83%B3%E6%9C%89%E4%B8%AA%E4%BF%A1%E4%BB%B0/blog/item/6a609243435479208
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trade
TRADE
trade
TRADE