f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2(0,+∞)增函数 f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2
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![f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2(0,+∞)增函数 f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2](/uploads/image/z/15032719-55-9.jpg?t=f%EF%BC%88x%C3%B7y%EF%BC%89%3Df%EF%BC%88x%EF%BC%89-f%EF%BC%88y%EF%BC%89+f%EF%BC%886%EF%BC%89%3D1+%E8%AF%81f%EF%BC%8836%EF%BC%89%3D2%E4%B8%8E%E6%8E%A5%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%88x%2B3%EF%BC%89-f%EF%BC%881%C3%B7x%EF%BC%89%EF%BC%9C2%EF%BC%880%2C%2B%E2%88%9E%EF%BC%89%E5%A2%9E%E5%87%BD%E6%95%B0+f%EF%BC%88x%C3%B7y%EF%BC%89%3Df%EF%BC%88x%EF%BC%89-f%EF%BC%88y%EF%BC%89+f%EF%BC%886%EF%BC%89%3D1+%E8%AF%81f%EF%BC%8836%EF%BC%89%3D2%E4%B8%8E%E6%8E%A5%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%88x%2B3%EF%BC%89-f%EF%BC%881%C3%B7x%EF%BC%89%EF%BC%9C2)
f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2(0,+∞)增函数 f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2
f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2
(0,+∞)增函数 f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2
f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2(0,+∞)增函数 f(x÷y)=f(x)-f(y) f(6)=1 证f(36)=2与接不等式f(x+3)-f(1÷x)<2
f(x/y)=f(x)-f(y)
f(36/6)=f(36)-f(6) =f(6)
所以f(36)=2f(6)=2
由f(x/y)=f(x)-f(y) 可以证明得 f(x)在(0,无穷大)上是增函数
所以 f(x+3)-f(1/x) =f((x+3)/(1/x))=f(x(x+3))
f(x/y)=f(x)-f(y)
f(36/6)=f(36)-f(6) =f(6)
所以f(36)=2f(6)=2
由f(x/y)=f(x)-f(y) 可以证明得 f(x)在(0,无穷大)上是增函数
所以 f(x+3)-f(1/x) =f((x+3)/(1/x))=f(x(x+3))<2=f(36)
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f(x/y)=f(x)-f(y)
f(36/6)=f(36)-f(6) =f(6)
所以f(36)=2f(6)=2
由f(x/y)=f(x)-f(y) 可以证明得 f(x)在(0,无穷大)上是增函数
所以 f(x+3)-f(1/x) =f((x+3)/(1/x))=f(x(x+3))<2=f(36)
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