已知函数f(x)=mx/2+(m-2)/2x(m>0)(1)若f(x)≥lnx+m-1在[1,+∞)上恒成立,求m的取值范围,(2)2ln2+3ln3+……+nlnn≤(2n^3+3n^2-5n)/12 (n∈N+)第(1)题已经做出来啦,只需要第(2)题.当n=1时,左边=1 ln1=
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![已知函数f(x)=mx/2+(m-2)/2x(m>0)(1)若f(x)≥lnx+m-1在[1,+∞)上恒成立,求m的取值范围,(2)2ln2+3ln3+……+nlnn≤(2n^3+3n^2-5n)/12 (n∈N+)第(1)题已经做出来啦,只需要第(2)题.当n=1时,左边=1 ln1=](/uploads/image/z/15135724-28-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dmx%2F2%2B%28m-2%29%2F2x%EF%BC%88m%EF%BC%9E0%EF%BC%89%EF%BC%881%EF%BC%89%E8%8B%A5f%28x%29%E2%89%A5lnx%2Bm-1%E5%9C%A8%5B1%2C%2B%E2%88%9E%EF%BC%89%E4%B8%8A%E6%81%92%E6%88%90%E7%AB%8B%2C%E6%B1%82m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%2C%EF%BC%882%EF%BC%892ln2%2B3ln3%2B%E2%80%A6%E2%80%A6%2Bnlnn%E2%89%A4%282n%5E3%2B3n%5E2-5n%29%2F12+%28n%E2%88%88N%2B%EF%BC%89%E7%AC%AC%EF%BC%881%EF%BC%89%E9%A2%98%E5%B7%B2%E7%BB%8F%E5%81%9A%E5%87%BA%E6%9D%A5%E5%95%A6%2C%E5%8F%AA%E9%9C%80%E8%A6%81%E7%AC%AC%EF%BC%882%EF%BC%89%E9%A2%98.%E5%BD%93n%3D1%E6%97%B6%EF%BC%8C%E5%B7%A6%E8%BE%B9%3D1+ln1%3D)
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