y=x^2-3x+2/x^2-x+1,判别式法

来源：学生作业帮助网 编辑：作业帮 时间：2024/07/18 09:17:36
y=x^2-3x+2/x^2-x+1,判别式法
x)3561* uv,yڱg$T_`gCI66=mt|{0=P]`)8a,D WY&Qk 0֭Ԭ4m rON5|6}gmTk57z{mdg'iApM:b 6h 2 vPs^,_ttKuu27/.H̳ cO;6<۴isT

y=x^2-3x+2/x^2-x+1,判别式法
y=x^2-3x+2/x^2-x+1,判别式法

y=x^2-3x+2/x^2-x+1,判别式法
求值域?
y=(x^2-3x+2)/(x^2-x+1)
(x^2-x+1)y=x^2-3x+2
yx^2-yx+y=x^2-3x+2
(y-1)x^2+(3-y)x+(y-2)=0
当y=1时
0+2x-1=0
x=1/2满足定义域R
当y≠1时
Δ=(3-y)^2-4(y-1)(y-2)>=0
解得
(3-2√3)/3

我发到河南省

函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x 化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x) 3^x+2x=y,x 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 y=(2x*x-2x+3)/(x*x-x+1),求值域? x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4) 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x x(x-y)2-(y-x)3 计算：1-2x+x^2/x-x^3*xy+x^2y/x-x^2 (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)