y=x^2-3x+2/x^2-x+1,判别式法
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y=x^2-3x+2/x^2-x+1,判别式法
y=x^2-3x+2/x^2-x+1,判别式法
y=x^2-3x+2/x^2-x+1,判别式法
求值域?
y=(x^2-3x+2)/(x^2-x+1)
(x^2-x+1)y=x^2-3x+2
yx^2-yx+y=x^2-3x+2
(y-1)x^2+(3-y)x+(y-2)=0
当y=1时
0+2x-1=0
x=1/2满足定义域R
当y≠1时
Δ=(3-y)^2-4(y-1)(y-2)>=0
解得
(3-2√3)/3
我发到河南省
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