设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=f(0)=0,f(1/2)=1,试证:至少存在一个§€(0,1),使f'(§)=1
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![设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=f(0)=0,f(1/2)=1,试证:至少存在一个§€(0,1),使f'(§)=1](/uploads/image/z/15199978-58-8.jpg?t=%E8%AE%BEf%28x%29%E5%9C%A8%5B0%2C1%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%9C%A8%EF%BC%880%2C1%29%E5%86%85%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%281%29%3Df%280%29%3D0%2Cf%281%2F2%29%3D1%2C%E8%AF%95%E8%AF%81%EF%BC%9A%E8%87%B3%E5%B0%91%E5%AD%98%E5%9C%A8%E4%B8%80%E4%B8%AA%C2%A7%26%238364%3B%280%2C1%29%2C%E4%BD%BFf%27%28%C2%A7%29%3D1)
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设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=f(0)=0,f(1/2)=1,试证:至少存在一个§€(0,1),使f'(§)=1
设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=f(0)=0,f(1/2)=1,试证:至少存在一个§€(0,1),使f'(§)=1
设f(x)在[0,1]上连续,在(0,1)内可导,且f(1)=f(0)=0,f(1/2)=1,试证:至少存在一个§€(0,1),使f'(§)=1
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