[2^2=1]*[2^4=1]*[2^8=1][2^16=1]运算过程及结果

2*4*8*...*2^(n-1)=? (2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=? 1/2+1/4+1/8+...+1/2n=? 3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=? （1+1/2)(1+1/2^2)(1+1/2^4）（1+1/2^8)+1/2^15=? (2^2+1)(2^4+1)(2^8+1)(2^16+1)=? 计算:(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/（2^32）-1=? (2+1)(2^2+1)(2^4+1) (2^8+1) (2^16+1) (2^32+1)=? 3*(2^2+1)(2^4+1)(2^8+1)(2^16+1)...(2^2n+1)+1= 1+1=2+2=4+4=8+8=16+16= [2^2=1]*[2^4=1]*[2^8=1][2^16=1]运算过程及结果 线性代数题,计算行列式(1)|4 2 2 2||2 4 2 2| =|2 2 4 2||2 2 2 4|(2)|1 1 1 1 ||1 2 3 4 | =|1 4 9 16||1 8 27 64| (2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1= 3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64= 阅读下题的解法,并完成提问1.(2+1)(2^2+1)(2^4+1)-2^8原式=(2-1)(2+1)(2^2+1)(2^4+1)-2^8=(2^2-1)(2^2+1)(2^4+1)-2^8=(2^4-1)(2^4+1)-2^8=(2^8-1)-2^8=-12.照1里的解法计算(10^2+1)(10^4+1)(10^8+1)*9900+100是多少? 已知M=(2+1)(2^2+1)(2^4+1)(2^8+1) ……(2^16已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)……(2^16+1)(2^128+1) 1+1/2+1/4+1/8+...1/64=? 数学题：（2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)+1=