函数f(x)=1/2sin(x-π/6)图像向右平移m个单位后图像关于原点对称,且0x+π/6+m-(x-π/6-m)=2π=>m=5π/6 问一下那步为什么等于2π
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![函数f(x)=1/2sin(x-π/6)图像向右平移m个单位后图像关于原点对称,且0x+π/6+m-(x-π/6-m)=2π=>m=5π/6 问一下那步为什么等于2π](/uploads/image/z/15222684-12-4.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3D1%2F2sin%28x-%CF%80%2F6%29%E5%9B%BE%E5%83%8F%E5%90%91%E5%8F%B3%E5%B9%B3%E7%A7%BBm%E4%B8%AA%E5%8D%95%E4%BD%8D%E5%90%8E%E5%9B%BE%E5%83%8F%E5%85%B3%E4%BA%8E%E5%8E%9F%E7%82%B9%E5%AF%B9%E7%A7%B0%2C%E4%B8%940x%2B%CF%80%2F6%2Bm-%28x-%CF%80%2F6-m%29%3D2%CF%80%3D%3Em%3D5%CF%80%2F6+%E9%97%AE%E4%B8%80%E4%B8%8B%E9%82%A3%E6%AD%A5%E4%B8%BA%E4%BB%80%E4%B9%88%E7%AD%89%E4%BA%8E2%CF%80)
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函数f(x)=1/2sin(x-π/6)图像向右平移m个单位后图像关于原点对称,且0x+π/6+m-(x-π/6-m)=2π=>m=5π/6 问一下那步为什么等于2π
函数f(x)=1/2sin(x-π/6)图像向右平移m个单位后图像关于原点对称,且0x+π/6+m-(x-π/6-m)=2π
=>m=5π/6 问一下那步为什么等于2π
函数f(x)=1/2sin(x-π/6)图像向右平移m个单位后图像关于原点对称,且0x+π/6+m-(x-π/6-m)=2π=>m=5π/6 问一下那步为什么等于2π
1/2sin(x-π/6-m)=1/2sin(x+π/6+m)
所以x-π/6-m和x+π/6+m相差的是周期的整数倍 也就是2kπ
x+π/6+m-(x-π/6-m)=2kπ k∈Z
m=5kπ/6
∵0
∵0<m<2π,显然x+π/6+m≠x-π/6-m ∴ x+π/6+m-(x-π/6-m)=2kπ,综合0<m<2π,得k=1,∴m=5π/6
祝学习愉快
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