lim[cos(1/x)]^2,x--->0,极限为什么不存在

lim x趋向0 (1+cos^2(1/x))^x lim(sin(x^2*cos(1/x)))/x怎么做? lim x->0 cos(2x)-1 / cosx -1 = lim[cos(1/x)]^2,x--->0,极限为什么不存在 lim(cos(sqrt(x)))^1/x 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim x->0 1-cos(3x)/(2x) 和 lim x->0 1-cos3x/2x^2 求lim (sec^2 x求极限lim (sec^2 x - 1 )/(1-cos x) X-0请写出过程, 用罗必达法则解 （见图）lim [(e^x)-1/sin（5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->∞ lim 7cos(3x)sec(9x)x->pi/2 高数题 lim(x-无穷大) x cos 1/x lim(x~无穷大) Xcos 1/X lim(x→0) [1-cos(x^2)]/sin(x^2)tan(x^2)]=? lim(x趋近于0)(（1/sin^2 x）-(cos^2 x)/x^2)= 求 lim(x→∞)[sin(2/x)+cos(1/x)]^x的极限. lim(x→0)(1/x)*cos(1/x) lim(x→0)(cosx-cos^2x)/x^2 lim(x->PI/2) COS X/(PI/2)-X 求函数极限：lim(x->0) (cos x)^(1/x) lim((cos( √x))^(1/x)) x……0+