lim(4/(x^2-4)+1/(x-2)= (n→2)算出来lim=-1/(x+2)答案是-1/4,我觉得是0是lim(4/(x^2-4)-1/(x-2)= (n→2)
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![lim(4/(x^2-4)+1/(x-2)= (n→2)算出来lim=-1/(x+2)答案是-1/4,我觉得是0是lim(4/(x^2-4)-1/(x-2)= (n→2)](/uploads/image/z/15246414-54-4.jpg?t=lim%284%2F%28x%5E2-4%29%2B1%2F%28x-2%29%3D+%EF%BC%88n%E2%86%922%EF%BC%89%E7%AE%97%E5%87%BA%E6%9D%A5lim%3D-1%2F%28x%2B2%29%E7%AD%94%E6%A1%88%E6%98%AF-1%2F4%2C%E6%88%91%E8%A7%89%E5%BE%97%E6%98%AF0%E6%98%AFlim%284%2F%28x%5E2-4%29-1%2F%28x-2%29%3D+%EF%BC%88n%E2%86%922%EF%BC%89)
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lim(4/(x^2-4)+1/(x-2)= (n→2)算出来lim=-1/(x+2)答案是-1/4,我觉得是0是lim(4/(x^2-4)-1/(x-2)= (n→2)
lim(4/(x^2-4)+1/(x-2)= (n→2)
算出来lim=-1/(x+2)答案是-1/4,我觉得是0
是lim(4/(x^2-4)-1/(x-2)= (n→2)
lim(4/(x^2-4)+1/(x-2)= (n→2)算出来lim=-1/(x+2)答案是-1/4,我觉得是0是lim(4/(x^2-4)-1/(x-2)= (n→2)
如果题没错的话应该是无穷大吧,按答案来看题应该是lim(4/(x^2-4)-1/(x-2))= (x→2)这样吧
既然改了题,那就对了.4/(x^2-4)可以写为[1/(x-2)]-[1/(x+2)],接下来抵消一项,直接带入x=2就ok了
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