如图所示,在四边形ABCD中,AD//BC,AB=DC=AD,∠ABC=∠C=60°,AE⊥BD于点E,F是CD的中点,求证:四边形AEFD是平行四边形如图所示,AD是△ABC的中线,F是AC上一点,且CF=2AF,连接BD交AD于点E,求证:BE=3EF
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 01:40:34
![如图所示,在四边形ABCD中,AD//BC,AB=DC=AD,∠ABC=∠C=60°,AE⊥BD于点E,F是CD的中点,求证:四边形AEFD是平行四边形如图所示,AD是△ABC的中线,F是AC上一点,且CF=2AF,连接BD交AD于点E,求证:BE=3EF](/uploads/image/z/1525161-57-1.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%9C%A8%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2CAD%2F%2FBC%2CAB%3DDC%3DAD%2C%E2%88%A0ABC%3D%E2%88%A0C%3D60%C2%B0%2CAE%E2%8A%A5BD%E4%BA%8E%E7%82%B9E%2CF%E6%98%AFCD%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E5%9B%9B%E8%BE%B9%E5%BD%A2AEFD%E6%98%AF%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2CAD%E6%98%AF%E2%96%B3ABC%E7%9A%84%E4%B8%AD%E7%BA%BF%2CF%E6%98%AFAC%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%B8%94CF%3D2AF%2C%E8%BF%9E%E6%8E%A5BD%E4%BA%A4AD%E4%BA%8E%E7%82%B9E%2C%E6%B1%82%E8%AF%81%EF%BC%9ABE%3D3EF)
xTnF@v9C,4.H!
Hm ]1FZHIjEQ[S-H ԕD)Ej0y9wHN^{ฒ?McvX2xV,NŲ)s*p8TGoW,wt͒Эxݾ&B2*?;']AP:|1Ai}~xf_-'KqV9|x[^eN*m5nyZ{O]Y~u$>]k}E*פMAך[[e9Xoͭz[beMv
a:BWSEHݠaCLC@ abEP6"\A"IL`D&m^
eX9*La @zD8GAX|e>TqIqSWCbDsGP3*0"!8Aj5%FrZUb 5b+y/ #USM6U#P#.X$8+.I'V}}`:Q;3UwV`nfi"(oOԲd1Zw2*ӥ:@