1.设X2+4Y2-4=0(X,Y∈R),求X2+Y2+6X的最值 2.A(-1,0)B(1,0)动点M满足向量AM,向量BM等于点M到C(0,1)距离平方的k倍.问点M的轨迹是怎样的曲线 3.过P(3,0)直线l叫X2/4+Y2/16=1于A,B两点,向量OA*向量OB=0,求
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![1.设X2+4Y2-4=0(X,Y∈R),求X2+Y2+6X的最值 2.A(-1,0)B(1,0)动点M满足向量AM,向量BM等于点M到C(0,1)距离平方的k倍.问点M的轨迹是怎样的曲线 3.过P(3,0)直线l叫X2/4+Y2/16=1于A,B两点,向量OA*向量OB=0,求](/uploads/image/z/15256523-11-3.jpg?t=1.%E8%AE%BEX2%2B4Y2-4%3D0%EF%BC%88X%2CY%E2%88%88R%EF%BC%89%2C%E6%B1%82X2%2BY2%2B6X%E7%9A%84%E6%9C%80%E5%80%BC+2.A%EF%BC%88-1%2C0%EF%BC%89B%EF%BC%881%2C0%EF%BC%89%E5%8A%A8%E7%82%B9M%E6%BB%A1%E8%B6%B3%E5%90%91%E9%87%8FAM%2C%E5%90%91%E9%87%8FBM%E7%AD%89%E4%BA%8E%E7%82%B9M%E5%88%B0C%280%2C1%29%E8%B7%9D%E7%A6%BB%E5%B9%B3%E6%96%B9%E7%9A%84k%E5%80%8D.%E9%97%AE%E7%82%B9M%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%98%AF%E6%80%8E%E6%A0%B7%E7%9A%84%E6%9B%B2%E7%BA%BF+3.%E8%BF%87P%EF%BC%883%2C0%EF%BC%89%E7%9B%B4%E7%BA%BFl%E5%8F%ABX2%2F4%2BY2%2F16%3D1%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E5%90%91%E9%87%8FOA%2A%E5%90%91%E9%87%8FOB%3D0%2C%E6%B1%82)
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