作业帮x^3-3xy^2+i(3xy^2-y^3)如何变成z^3
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x^3-3xy^2+i(3xy^2-y^3)如何变成z^3
x^3-3xy^2+i(3xy^2-y^3)如何变成z^3
x^3-3xy^2+i(3xy^2-y^3)如何变成z^3
x^3-3xy^2+i(3xy^2-y^3)
=x^3+3x(yi)^2+i3xy^2+(yi)^3
=(x+yi)^3
=z^3
是i(3x²y-y³)
原式=x³+3x(yi)²+3x²(yi)+(yi)³
=(x+yi)³
2x²y-3(2xy-xy)-xy
（X-3xy+4xy-y）-[-2x-2（xy-3/2xy）-y]+6xy的过程
xy-2{xy-[3x^2y-(4xy^2+0.5xy)]+4x^2y}+6xy^2
3xy(x^2y-xy^2+xy)-xy^2(2x^2-6xy+2x)过程
计算：3xy(x²y-xy²+xy)-xy²(2x-xy+2x）
【x(xy-xy)-y(x-xy)】÷3xy
x^2-xy-6y^2+3xy+y+2
计算：3xy[2xy-x（y-2）+x]
计算3xy[2xy-x(y-2)+x-1]
（-3x^y+2xy)-( )=4x^+xy
化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy]
(-3xy+2xy)-(4xy+xy)
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2
5x^3y*(-3y)^2+(-6xy)^2*(-xy)+xy^3*(-4x^2)
x^3-3xy^2+i(3xy^2-y^3)如何变成z^3
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
计算题 xy【y^2+x^2】-y^2【xy+2x】-3xy
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解