40(2-y)=16(4-y)=10(x-y),
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40(2-y)=16(4-y)=10(x-y),
40(2-y)=16(4-y)=10(x-y),
40(2-y)=16(4-y)=10(x-y),
40(2-y)=16(4-y)=10(x-y),
y'=(y/x)^2+y/x+4微分方程
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