一道数学证明题(说一下思路就行)锐角三角形ABC,分别以AB、AC为边作正方形,M为BC边上的中点,求证EF=2AM注:那个M点我忘了标上去
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![一道数学证明题(说一下思路就行)锐角三角形ABC,分别以AB、AC为边作正方形,M为BC边上的中点,求证EF=2AM注:那个M点我忘了标上去](/uploads/image/z/1526492-20-2.jpg?t=%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E8%AF%81%E6%98%8E%E9%A2%98%EF%BC%88%E8%AF%B4%E4%B8%80%E4%B8%8B%E6%80%9D%E8%B7%AF%E5%B0%B1%E8%A1%8C%EF%BC%89%E9%94%90%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2C%E5%88%86%E5%88%AB%E4%BB%A5AB%E3%80%81AC%E4%B8%BA%E8%BE%B9%E4%BD%9C%E6%AD%A3%E6%96%B9%E5%BD%A2%2CM%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E6%B1%82%E8%AF%81EF%3D2AM%E6%B3%A8%EF%BC%9A%E9%82%A3%E4%B8%AAM%E7%82%B9%E6%88%91%E5%BF%98%E4%BA%86%E6%A0%87%E4%B8%8A%E5%8E%BB)
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