已知直线L的方向向量a=(1,3),直线L′的方向向量为b=(-1,k).若直线L′经过点(0,5)且L⊥L′,则直线L′的方程是什么.上面为原题目书上给的答案是∵a=(1,3) ,b=(-1,k),∴a·b=-1+3k=0∴k=1/3.又因为直线L′经
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![已知直线L的方向向量a=(1,3),直线L′的方向向量为b=(-1,k).若直线L′经过点(0,5)且L⊥L′,则直线L′的方程是什么.上面为原题目书上给的答案是∵a=(1,3) ,b=(-1,k),∴a·b=-1+3k=0∴k=1/3.又因为直线L′经](/uploads/image/z/1581251-59-1.jpg?t=%E5%B7%B2%E7%9F%A5%E7%9B%B4%E7%BA%BFL%E7%9A%84%E6%96%B9%E5%90%91%E5%90%91%E9%87%8Fa%3D%281%2C3%29%2C%E7%9B%B4%E7%BA%BFL%E2%80%B2%E7%9A%84%E6%96%B9%E5%90%91%E5%90%91%E9%87%8F%E4%B8%BAb%3D%28-1%2Ck%29.%E8%8B%A5%E7%9B%B4%E7%BA%BFL%E2%80%B2%E7%BB%8F%E8%BF%87%E7%82%B9%280%2C5%29%E4%B8%94L%E2%8A%A5L%E2%80%B2%2C%E5%88%99%E7%9B%B4%E7%BA%BFL%E2%80%B2%E7%9A%84%E6%96%B9%E7%A8%8B%E6%98%AF%E4%BB%80%E4%B9%88.%E4%B8%8A%E9%9D%A2%E4%B8%BA%E5%8E%9F%E9%A2%98%E7%9B%AE%E4%B9%A6%E4%B8%8A%E7%BB%99%E7%9A%84%E7%AD%94%E6%A1%88%E6%98%AF%E2%88%B5a%3D%281%2C3%29+%2Cb%3D%28-1%2Ck%29%2C%E2%88%B4a%C2%B7b%3D-1%2B3k%3D0%E2%88%B4k%3D1%2F3.%E5%8F%88%E5%9B%A0%E4%B8%BA%E7%9B%B4%E7%BA%BFL%E2%80%B2%E7%BB%8F)
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