设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c
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![设△ABC的内角A,B,C所对的边长分别为a,b,c,a=2根号3,tan((A+B)/2)+tan(c/2)=4,2sinBcosC=sinA,求A,B及b,c](/uploads/image/z/1603938-66-8.jpg?t=%E8%AE%BE%E2%96%B3ABC%E7%9A%84%E5%86%85%E8%A7%92A%2CB%2CC%E6%89%80%E5%AF%B9%E7%9A%84%E8%BE%B9%E9%95%BF%E5%88%86%E5%88%AB%E4%B8%BAa%2Cb%2Cc%2Ca%3D2%E6%A0%B9%E5%8F%B73%2Ctan%28%28A%2BB%29%2F2%29%2Btan%28c%2F2%29%3D4%2C2sinBcosC%3DsinA%2C%E6%B1%82A%2CB%E5%8F%8Ab%2Cc)
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