已知一元二次方程ax²-√2bx+c=0的两个根满足 |x1-x2| =√2,且a,b,c分别是三角形ABC的角A,角B,角C的对边.证明方程的两个根都是正根,若a=c,求∠B的∠度数.
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![已知一元二次方程ax²-√2bx+c=0的两个根满足 |x1-x2| =√2,且a,b,c分别是三角形ABC的角A,角B,角C的对边.证明方程的两个根都是正根,若a=c,求∠B的∠度数.](/uploads/image/z/1603972-28-2.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bax%26sup2%3B-%E2%88%9A2bx%2Bc%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%A0%B9%E6%BB%A1%E8%B6%B3+%7Cx1-x2%7C+%3D%E2%88%9A2%2C%E4%B8%94a%2Cb%2Cc%E5%88%86%E5%88%AB%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E8%A7%92A%2C%E8%A7%92B%2C%E8%A7%92C%E7%9A%84%E5%AF%B9%E8%BE%B9.%E8%AF%81%E6%98%8E%E6%96%B9%E7%A8%8B%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%A0%B9%E9%83%BD%E6%98%AF%E6%AD%A3%E6%A0%B9%2C%E8%8B%A5a%EF%BC%9Dc%2C%E6%B1%82%E2%88%A0B%E7%9A%84%E2%88%A0%E5%BA%A6%E6%95%B0.)
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