一道超级难做的数学题已知f(x)=x^2-4,设曲线y=f(x)在点(Xn,f(Xn))处切线与x轴的交点为(Xn+1)(n∈N*)其中Xn为正实数(1)a1=4,记lg((Xn+2)/(Xn-2)),证明数列{an}成等比数列,并求数列{xn}
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![一道超级难做的数学题已知f(x)=x^2-4,设曲线y=f(x)在点(Xn,f(Xn))处切线与x轴的交点为(Xn+1)(n∈N*)其中Xn为正实数(1)a1=4,记lg((Xn+2)/(Xn-2)),证明数列{an}成等比数列,并求数列{xn}](/uploads/image/z/1607167-55-7.jpg?t=%E4%B8%80%E9%81%93%E8%B6%85%E7%BA%A7%E9%9A%BE%E5%81%9A%E7%9A%84%E6%95%B0%E5%AD%A6%E9%A2%98%E5%B7%B2%E7%9F%A5f%28x%29%3Dx%5E2-4%2C%E8%AE%BE%E6%9B%B2%E7%BA%BFy%3Df%28x%29%E5%9C%A8%E7%82%B9%EF%BC%88Xn%2Cf%EF%BC%88Xn%EF%BC%89%EF%BC%89%E5%A4%84%E5%88%87%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E7%9A%84%E4%BA%A4%E7%82%B9%E4%B8%BA%EF%BC%88Xn%2B1%EF%BC%89%EF%BC%88n%E2%88%88N%2A%EF%BC%89%E5%85%B6%E4%B8%ADXn%E4%B8%BA%E6%AD%A3%E5%AE%9E%E6%95%B0%EF%BC%881%EF%BC%89a1%3D4%2C%E8%AE%B0lg%EF%BC%88%EF%BC%88Xn%2B2%EF%BC%89%2F%EF%BC%88Xn-2%EF%BC%89%EF%BC%89%2C%E8%AF%81%E6%98%8E%E6%95%B0%E5%88%97%7Ban%7D%E6%88%90%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E5%B9%B6%E6%B1%82%E6%95%B0%E5%88%97%7Bxn%7D)
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