已知关于x的一元二次方程x²+2(a-1)x+a²-7a-4=0的两根为x1,x2,且满足x1x2-3x1-3x2-2=0.求[1+﹙a²-4﹚分之4]乘a分之a+2的值.
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![已知关于x的一元二次方程x²+2(a-1)x+a²-7a-4=0的两根为x1,x2,且满足x1x2-3x1-3x2-2=0.求[1+﹙a²-4﹚分之4]乘a分之a+2的值.](/uploads/image/z/1613956-4-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%B3%E4%BA%8Ex%E7%9A%84%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%26%23178%3B%2B2%28a-1%29x%2Ba%26%23178%3B%EF%BC%8D7a%EF%BC%8D4%EF%BC%9D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B8%BAx1%2Cx2%2C%E4%B8%94%E6%BB%A1%E8%B6%B3x1x2%EF%BC%8D3x1%EF%BC%8D3x2%EF%BC%8D2%3D0.%E6%B1%82%5B1%2B%EF%B9%99a%26%23178%3B%EF%BC%8D4%EF%B9%9A%E5%88%86%E4%B9%8B4%5D%E4%B9%98a%E5%88%86%E4%B9%8Ba%2B2%E7%9A%84%E5%80%BC.)
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