已知二次函数f(x)=ax的平方+x,若X属于【0 1】时有f(x)的绝对值小于等于1恒成立,则实数af(x)=-x满足,对于任意的 属于【0,1】都有f()-f()的绝对值小于等于1恒成立,则a的取值范围
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![已知二次函数f(x)=ax的平方+x,若X属于【0 1】时有f(x)的绝对值小于等于1恒成立,则实数af(x)=-x满足,对于任意的 属于【0,1】都有f()-f()的绝对值小于等于1恒成立,则a的取值范围](/uploads/image/z/1626953-41-3.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%28x%29%3Dax%E7%9A%84%E5%B9%B3%E6%96%B9%2Bx%2C%E8%8B%A5X%E5%B1%9E%E4%BA%8E%E3%80%900+1%E3%80%91%E6%97%B6%E6%9C%89f%28x%29%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E1%E6%81%92%E6%88%90%E7%AB%8B%2C%E5%88%99%E5%AE%9E%E6%95%B0af%28x%29%3D-x%E6%BB%A1%E8%B6%B3%2C%E5%AF%B9%E4%BA%8E%E4%BB%BB%E6%84%8F%E7%9A%84+%E5%B1%9E%E4%BA%8E%E3%80%900%2C1%E3%80%91%E9%83%BD%E6%9C%89f%28%29-f%28%29%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E1%E6%81%92%E6%88%90%E7%AB%8B%2C%E5%88%99a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
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