设f(x)=x立方+log2(x+√(x平方+1))则对任意实数a,b,a+b>=0是f(a)+f(b)>=0的什么条件为什么log2(-x+√(x^2+1))=log2[1/(x+√(x^2+1))]?
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![设f(x)=x立方+log2(x+√(x平方+1))则对任意实数a,b,a+b>=0是f(a)+f(b)>=0的什么条件为什么log2(-x+√(x^2+1))=log2[1/(x+√(x^2+1))]?](/uploads/image/z/1631568-48-8.jpg?t=%E8%AE%BEf%EF%BC%88x%EF%BC%89%3Dx%E7%AB%8B%E6%96%B9%2Blog2%EF%BC%88x%2B%E2%88%9A%EF%BC%88x%E5%B9%B3%E6%96%B9%2B1%EF%BC%89%EF%BC%89%E5%88%99%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0a%2Cb%2Ca%2Bb%EF%BC%9E%EF%BC%9D0%E6%98%AFf%EF%BC%88a%EF%BC%89%2Bf%EF%BC%88b%EF%BC%89%EF%BC%9E%3D0%E7%9A%84%E4%BB%80%E4%B9%88%E6%9D%A1%E4%BB%B6%E4%B8%BA%E4%BB%80%E4%B9%88log2%28%EF%BC%8Dx%2B%E2%88%9A%28x%EF%BC%BE2%2B1%29%29%EF%BC%9Dlog2%5B1%2F%28x%2B%E2%88%9A%28x%EF%BC%BE2%2B1%29%29%5D%EF%BC%9F)
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