(x-42):(x-6)=40:(40+12)怎么解详细点
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(x-42):(x-6)=40:(40+12)怎么解详细点
(x-42):(x-6)=40:(40+12)怎么解详细点
(x-42):(x-6)=40:(40+12)怎么解详细点
写成分式,两边的分子同乘以-1加到分母上变为
(x-42)/36=40/12
x-42=40*3=120
x=162
(x-42):(x-6)=40:(40+12)
52(x-42)=40(x-6)
52x-2184=40x-240
52x-40x=2184-240
12x=1944
x=1944/12
x=162
解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解
x-x-6=40
x-40%x=
8x+(5-x)X12=52 9x-26=4.5x=14.59-0.72x=6-0.12x 40x-20+42=108
x-40%x-40%x=15
18x+[5-x]=40+6x
18x+[5-x]2=40+6x
(x+6)/(40+x)=20%求x.
x+40=2x x=?
解方程 X+40%X=42
X×X+(40-X)=58
X乘以X等于40 ---------------------X=?
10x+x*x=40
(x+40%x)×85%-x=95
(x+40%x)×85%-x=95
4x+x=40x
40%x+70%x-x=1.8
40%x-50%x=6