{x+y-z=2 4x-2y+3z+8=0 x+3y-2z-6=0怎么解?

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 2x+z=10 x+y-z=4 3x-y-z=0 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=? x+y+z=-1 4x-2y+3z=5 y-z=8-2x 2x+3y+z=8 4x-y-z=10 x+2y-z=1 三元一次方程 X+Y+Z=6 2X+3Y-Z=4 3X-Y+Z=8 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian 已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z= 已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值