14.如图.△ABC为等腰三角形,△DBC和△ACE分别为等边三角形,AE与BD相交于点F,连接CF并延长,交AB于G求证 G为AB中点
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![14.如图.△ABC为等腰三角形,△DBC和△ACE分别为等边三角形,AE与BD相交于点F,连接CF并延长,交AB于G求证 G为AB中点](/uploads/image/z/1639093-13-3.jpg?t=14.%E5%A6%82%E5%9B%BE.%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E2%96%B3DBC%E5%92%8C%E2%96%B3ACE%E5%88%86%E5%88%AB%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CAE%E4%B8%8EBD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9F%2C%E8%BF%9E%E6%8E%A5CF%E5%B9%B6%E5%BB%B6%E9%95%BF%2C%E4%BA%A4AB%E4%BA%8EG%E6%B1%82%E8%AF%81+G%E4%B8%BAAB%E4%B8%AD%E7%82%B9)
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