求y=(5x^2+8x+5)/(x+1) 的值域求值域问题

(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) {(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=? x+y=8 2x-y=1 求3x+5y 求y=(5x-1)/(4x+2) (x 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 已知x>-1,求y=(x+1)/(x^2+5x+8)的最大值 y=x^3-5x^2+2x-8 求y^2求y撇 3X+2Y=5X+2 2(3X+2Y)=2X+8 求 X Y 求值域 1.y=-x+x+2,x∈(-1,2] 2.y=8/x-4x+5 3.y=x-2√x求值域1.y=-x+x+2,x∈(-1,2]2.y=8/x-4x+53.y=x-2√x+3 y=(2x^2+3x+8)/x+1 求值域 y=-2x^2+4x+5(x>2) 求值域 求(X+Y)(X-Y)(X²+Y²),X=5 Y=2, 求y=(5x^2+8x+5)/(x+1) 的值域求值域问题 已知:3x-5y=0,求x/y,x-y/y,x-y/x 已知x-2y=2016,求[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以8x的值 已知x-2y=2012,求[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/(8x)) x-2y=2008求{(3x+2y)(3x-2y)-(x+2y)(5x-2y)}/8x 已知x-2y=2010,求[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷8x的值 已知:x-2y=2009,求[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以8x 的值