已知抛物线C,y^2=4x的焦点为F,过点K(-1,0)的直线L与C相交与A,B两点,点A关于X轴的对称点为D.1,证明:点F在直线BD上.2,设向量FA×向量FB=8/9,求三角形BDK的内切圆MC的方程.
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![已知抛物线C,y^2=4x的焦点为F,过点K(-1,0)的直线L与C相交与A,B两点,点A关于X轴的对称点为D.1,证明:点F在直线BD上.2,设向量FA×向量FB=8/9,求三角形BDK的内切圆MC的方程.](/uploads/image/z/1671674-50-4.jpg?t=%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFC%2Cy%5E2%3D4x%E7%9A%84%E7%84%A6%E7%82%B9%E4%B8%BAF%2C%E8%BF%87%E7%82%B9K%28-1%2C0%29%E7%9A%84%E7%9B%B4%E7%BA%BFL%E4%B8%8EC%E7%9B%B8%E4%BA%A4%E4%B8%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E7%82%B9A%E5%85%B3%E4%BA%8EX%E8%BD%B4%E7%9A%84%E5%AF%B9%E7%A7%B0%E7%82%B9%E4%B8%BAD.1%2C%E8%AF%81%E6%98%8E%EF%BC%9A%E7%82%B9F%E5%9C%A8%E7%9B%B4%E7%BA%BFBD%E4%B8%8A.2%2C%E8%AE%BE%E5%90%91%E9%87%8FFA%C3%97%E5%90%91%E9%87%8FFB%3D8%2F9%2C%E6%B1%82%E4%B8%89%E8%A7%92%E5%BD%A2BDK%E7%9A%84%E5%86%85%E5%88%87%E5%9C%86MC%E7%9A%84%E6%96%B9%E7%A8%8B.)
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