已知a,b是实数且满足(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为
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已知a,b是实数且满足(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为
已知a,b是实数且满足(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为
已知a,b是实数且满足(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为
设 a²+b²=x
很显然 x>0
则原方程为
x²-x-6=0
1 2
1 -3
(x+2)(x-3)=0
x=3 (x=-2不符合x>0 舍去)
则
a²+b²=3
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