In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
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![In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.](/uploads/image/z/1676479-31-9.jpg?t=In+one+model+of+the+hydrogen+atom%2Cthe+electron+revolves+in+a+circular+orbit+around+the+proton+with+a+speed+of+2.0106m%2Fs.Determine+the+radius+of+the+electron%27s+orbit.)
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
kQq/r²=mv²/r
k=9×10^9N·m²/C²
Q=q=1.6×10^-19C
m=9.1×10^-31kg
r=kQq/mv²(速度不对吧,那么慢的电子,怎么也该是它的几十万、上百万倍)
(先按2×10^6m/s算)= 6.3×10^-11m=63pm
在氢原子模型中,电子以2.0106m/s的速度围绕中子转,求电子轨道的半径。
题意:氢原子中电子速度2.0106,求电子到中心距离。
同意楼上
电子速度是不是2.0*10^6m/s
也许这样比较符合实际