计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-(1+1/2+1/3+……+1/2006)(1/2+1/3+……+1/2005)为什么中间有没符号的..怎么计算啊.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 16:28:54
![计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-(1+1/2+1/3+……+1/2006)(1/2+1/3+……+1/2005)为什么中间有没符号的..怎么计算啊.](/uploads/image/z/1681884-36-4.jpg?t=%E8%AE%A1%E7%AE%97%3A%281%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2006%EF%BC%89%EF%BC%881%2B1%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2005%EF%BC%89-%3A%281%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2006%EF%BC%89%EF%BC%881%2B1%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2005%EF%BC%89-%EF%BC%881%2B1%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2006%EF%BC%89%EF%BC%881%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F2005%EF%BC%89%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%AD%E9%97%B4%E6%9C%89%E6%B2%A1%E7%AC%A6%E5%8F%B7%E7%9A%84..%E6%80%8E%E4%B9%88%E8%AE%A1%E7%AE%97%E5%95%8A.)
计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-(1+1/2+1/3+……+1/2006)(1/2+1/3+……+1/2005)为什么中间有没符号的..怎么计算啊.
计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-
:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-(1+1/2+1/3+……+1/2006)(1/2+1/3+……+1/2005)
为什么中间有没符号的..怎么计算啊.
计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-(1+1/2+1/3+……+1/2006)(1/2+1/3+……+1/2005)为什么中间有没符号的..怎么计算啊.
令1/2+1/3+……+1/2006=a,1/2+1/3+……+1/2005=b
则,原式=a(1+b)-(1+a)b
=a+ab-b-ab
=a-b
将a,b代入,得
a-b=1/2006
123
方程和规律算
你在列方程的时候一样也要用点表示。
找规律
1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111000000000000000000000000000000000000000000000000000000000 绝对正确 呵呵
令1/2+1/3+……+1/2006=a,1/2+1/3+……+1/2005=b
则,原式=a(1+b)-(1+a)b
=a+ab-b-ab
=a-b
将a,b代入,得
a-b=1/2006
a-b=1/2006
设1/2+1/3+……+1/2006=a,1/2+1/3+……+1/2005=b
原式=a(1+b)-(1+a)b
=a+ab-b-ab
=a-b
将a,b代入,得
a-b=1/2006