利用正切函数单调性比较 函数值大小tan [(75/11)π]&tan [(-58/11)π]这样可不可以 下面算式有错吗tan[(75/11)π] = tan[(9/11)π] =tan[(1-2/11)π] = -tan 2/11 πtan [(-58/11)π] = tan [-(8/11)π] = -tan[(1-3/11)π] = tan 3/11 π
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![利用正切函数单调性比较 函数值大小tan [(75/11)π]&tan [(-58/11)π]这样可不可以 下面算式有错吗tan[(75/11)π] = tan[(9/11)π] =tan[(1-2/11)π] = -tan 2/11 πtan [(-58/11)π] = tan [-(8/11)π] = -tan[(1-3/11)π] = tan 3/11 π](/uploads/image/z/1691058-66-8.jpg?t=%E5%88%A9%E7%94%A8%E6%AD%A3%E5%88%87%E5%87%BD%E6%95%B0%E5%8D%95%E8%B0%83%E6%80%A7%E6%AF%94%E8%BE%83+%E5%87%BD%E6%95%B0%E5%80%BC%E5%A4%A7%E5%B0%8Ftan+%5B%2875%2F11%29%CF%80%5D%26tan+%5B%28-58%2F11%29%CF%80%5D%E8%BF%99%E6%A0%B7%E5%8F%AF%E4%B8%8D%E5%8F%AF%E4%BB%A5+%E4%B8%8B%E9%9D%A2%E7%AE%97%E5%BC%8F%E6%9C%89%E9%94%99%E5%90%97tan%5B%2875%2F11%29%CF%80%5D+%3D+tan%5B%289%2F11%29%CF%80%5D+%3Dtan%5B%281-2%2F11%29%CF%80%5D+%3D+-tan+2%2F11+%CF%80tan+%5B%28-58%2F11%29%CF%80%5D+%3D+tan+%5B-%288%2F11%29%CF%80%5D+%3D+-tan%5B%281-3%2F11%29%CF%80%5D+%3D+tan+3%2F11+%CF%80)
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