如图,三角形ABC中,AC=BC,AC垂直BC,角CAB=角B=45度,D1,D2,...Dn-1是边CB上的n等分点,从C作AD1的垂线剩下的题目在这:分别交AD1,AD2,...ADn-1,AB于P1,P2,...Pn-1,Pn点,连接PnDn-1求证:角AD1C=角BDn-1Pn
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![如图,三角形ABC中,AC=BC,AC垂直BC,角CAB=角B=45度,D1,D2,...Dn-1是边CB上的n等分点,从C作AD1的垂线剩下的题目在这:分别交AD1,AD2,...ADn-1,AB于P1,P2,...Pn-1,Pn点,连接PnDn-1求证:角AD1C=角BDn-1Pn](/uploads/image/z/1692615-39-5.jpg?t=%E5%A6%82%E5%9B%BE%2C%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAC%3DBC%2CAC%E5%9E%82%E7%9B%B4BC%2C%E8%A7%92CAB%3D%E8%A7%92B%3D45%E5%BA%A6%2CD1%2CD2%2C...Dn-1%E6%98%AF%E8%BE%B9CB%E4%B8%8A%E7%9A%84n%E7%AD%89%E5%88%86%E7%82%B9%2C%E4%BB%8EC%E4%BD%9CAD1%E7%9A%84%E5%9E%82%E7%BA%BF%E5%89%A9%E4%B8%8B%E7%9A%84%E9%A2%98%E7%9B%AE%E5%9C%A8%E8%BF%99%3A%E5%88%86%E5%88%AB%E4%BA%A4AD1%2CAD2%2C...ADn-1%2CAB%E4%BA%8EP1%2CP2%2C...Pn-1%2CPn%E7%82%B9%2C%E8%BF%9E%E6%8E%A5PnDn-1%E6%B1%82%E8%AF%81%3A%E8%A7%92AD1C%3D%E8%A7%92BDn-1Pn)
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