f'[sin^2(x)]=cos^2(x),求f(x)用不定积分
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f'[sin^2(x)]=cos^2(x),求f(x)用不定积分
f'[sin^2(x)]=cos^2(x),求f(x)
用不定积分
f'[sin^2(x)]=cos^2(x),求f(x)用不定积分
原式可化为:
f'(sin²x)=cos²x=1-sin²x
所以f'(x)=1-x
两边积分得:
f(x)=x-(1/2)x²+C C为任意常数
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