已知x+y=2,xy=-5求(1)1/x+1/y的值 (2)求1/x²+1/y²的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 20:47:26
![已知x+y=2,xy=-5求(1)1/x+1/y的值 (2)求1/x²+1/y²的值](/uploads/image/z/1730592-0-2.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D2%2Cxy%3D-5%E6%B1%82%EF%BC%881%291%2Fx%2B1%2Fy%E7%9A%84%E5%80%BC+%EF%BC%882%EF%BC%89%E6%B1%821%2Fx%26%23178%3B%2B1%2Fy%26%23178%3B%E7%9A%84%E5%80%BC)
xQKPJ:;4
#EA"Zݙh!DYkVF4s?s6:le̠3)¯NKWb*"y*yfE:{h.P@,9Әn\iDM:
UQVl4jι .Bn-
~?D\GDiEe8U;kvV0+`)_\ퟡ1tiacmVE:P藸ߵmw$}3wg} }Gr
已知x+y=2,xy=-5求(1)1/x+1/y的值 (2)求1/x²+1/y²的值
已知x+y=2,xy=-5求(1)1/x+1/y的值 (2)求1/x²+1/y²的值
已知x+y=2,xy=-5求(1)1/x+1/y的值 (2)求1/x²+1/y²的值
已知x+y=2,xy=-5求
(1)1/x+1/y的值
=(x+y)/(xy)
=2/(-5)
=-2/5;
(2)求1/x²+1/y²的值
=(x²+y²)/(x²y²)
=[(x+y)²-2xy]/(x²y²)
=[2²+10]/25
=14/25;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
已知x+y=2,xy=-5
(1)1/x+1/y=[xy(1/x+1/y)/(xy)=(x+y)/(xy)=-2/5
(2)1/x²+1/y²=[x²y²(1/x²+1/y²)/(x²y²)=(y²+x²)/(xy)²=[(x+y)²-2xy]/(xy)²=14/25
希望能够帮助你,有疑问欢迎追问,祝学习进步!
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+2(xy+y)的值
【数学】已知 1/x-1/y=3 求 5x-xy-5y / x-2xy-y=?已知 1/x=1/y 求 2x-3xy-2y / x-2xy-y=?
已知(1/x)-(1/y)=5,求(2x+5xy-2y)/(x-2xy-y)
已知1/x-1/y=2,求5x+3xy-5y/x-2xy-y
已知1/x-1/y=5,求分式2x+5xy-2y/3x-xy-3y
已知 1/x-1/y=2,求2x+5xy-2y/x-2xy-y
已知1/x+1/y=5 求2x-3xy+2y/3x+2xy+3y
已知1/x+1/y=5 求2x-3xy+2y/x+2xy+y
已知1/x-1/y=2,求x-y-5xy/2x-2y+3xy
已知1/x+1/y=5,求x+2xy+y/2x-3xy+2y的值如题.
已知:1/X+1/Y=5,求 2x-3xy+2y/x+2xy+y的值,
已知1/x+1/y=1/2,求代数式3x-5xy+3y/-x+3xy-y
已知1/x-1/y=3,求5x+3xy-5y/x-2xy-y的值
已知1/x-1/y=3,求x-2xy-y/5x+3xy-5y的值
已知1/x-1/y=3,求5x+3xy-5y/x-2xy-y的值.
已知1/x-1/y=3,求5x+3xy-5y/x-2xy-y的值
已知1/X-1/y=3,求(5x+3xy-5y)/(x-2xy-y)的值