1.1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .+1/（a+2003)(a+2004)2.1/x - 1/x-1 （x²-1/x -x+1）3.1/a+2 + a-22.(1/x)- (1/x-1)【（x²-1/x）-x+1】用小括号括的是一个分式前面是分子后面是分母3.（1/a+2）+a-2

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1.1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .+1/（a+2003)(a+2004)2.1/x - 1/x-1 （x²-1/x -x+1）3.1/a+2 + a-22.(1/x)- (1/x-1)【（x²-1/x）-x+1】用小括号括的是一个分式前面是分子后面是分母3.（1/a+2）+a-2
1.1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .+1/（a+2003)(a+2004)
2.1/x - 1/x-1 （x²-1/x -x+1）
3.1/a+2 + a-2
2.(1/x)- (1/x-1)【（x²-1/x）-x+1】用小括号括的是一个分式前面是分子后面是分母
3.（1/a+2）+a-2

1.1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .+1/（a+2003)(a+2004)2.1/x - 1/x-1 （x²-1/x -x+1）3.1/a+2 + a-22.(1/x)- (1/x-1)【（x²-1/x）-x+1】用小括号括的是一个分式前面是分子后面是分母3.（1/a+2）+a-2
1. 1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .+1/（a+2003)(a+2004)
=1a-1/(a+1) + 1/(a+1)-1/(a+2) +1/(a+2)+.-1/(a+2003)+1/(a+2003)-1/a+2004)
=1/a-1/(a+2004)
=(a+2004-a)/{a(a+2004)
=2004/{a(a+2004)
2. 1/x - 1/x-1 （x²-1/x -x+1）
= 1/x - 1/(x-1) {(x^2-1) -x(x-1)}/x
= 1/x - 1/(x-1) {(x^2-1 -x^2 +x)}/x
= 1/x - 1/(x-1)*(x-1)/x
= 1/x - 1/x
=0
3. 1/(a+2) + ( a-2)
={1+(a+2)(a-2)}/(a+2)
={1+a^2-4)}/(a+2)
=(a^2-3)/(a+2)

1用分解，1/a(a+1)=1/a-1/(a+1).用这个分解方法分解所有项，然后相消。只余下第一项和最后项相减，答案简单，自己算算吧。这个是思路
你第二三两题写得不明白，麻烦写清楚包括括号一类的。我再回答

1. 1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .........+1/（a+2003)(a+2004)
=[1a-1/(a+1)]+[1/(a+1)-1/(a+2)]+[1/(a+2)-1/(a+3)]+.....+[1/(a+2003)-1/(a+2004)]
=1a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+...

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1. 1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .........+1/（a+2003)(a+2004)
=[1a-1/(a+1)]+[1/(a+1)-1/(a+2)]+[1/(a+2)-1/(a+3)]+.....+[1/(a+2003)-1/(a+2004)]
=1a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+.....+1/(a+2003)-1/(a+2004)
=1/a-1/(a+2004)
=(a+2004)/a(a+20004)-a/a(a+2004)
=(a+2004-a)/a(a+2004)
=2004/a(a+2004)
2. 1/x - 1/(x-1)* （x²-1/x -x+1）
=1/x-1(x-1)*[(x+1)(x-1)/x-(x-1)]
=1/x-[(x+1)/x-1]
=1/x-(1+1/x-1)
=1/x-1-1/x+1
=2
3. 1/(a+2) + a-2
=1/(a+2)+(a-2)*(a+2)/(a+2)
=(1+a^-4)/(a+2)
=(a^-3)/(a+2)

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1. 1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .........+1/（a+2003)(a+2004)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+.....+1/(a+2003)-1/(a+2004)
=1/a-1/(a+2004)
=(a+2004)/[a(a+2004)...

全部展开

1. 1/a(a+1) + 1/（a+1)(a+2) + 1/（a+2)(a+3) + .........+1/（a+2003)(a+2004)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+.....+1/(a+2003)-1/(a+2004)
=1/a-1/(a+2004)
=(a+2004)/[a(a+2004)]-a/[a(a+2004)]
=(a+2004-a)/[a(a+2004)]
=2004/[a(a+2004)]
2. 1/x - 1/x-1(x²-1/(x -x+1)?????
3. 1/a+2 + a-2???????

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1、数学判断|a*a*a|大于|-a*-a*-a| ( ) 化简:-a+a/a+1 因式分解:a-a-a+1 (a 1)(a 2)(a 3)(a (a+2)(a+1)-a(a-3) a*a*a*a+a*a+1/a*a+a+1 化简 A-A=0 A+A=?A÷A=1 A×A=?(A+A)+(A-A)+(AxA+A÷A）=100 A=? 怎么计算(a+1)(a*a+1)a*a*a*a+1).a(100)+1) a-1/a+2 求a(a-1) 4a-1/a 1-a/-2-a -2×a×1/a (a-1)(a-3) 计算：1-a-a(1-a)-a(1-a) 计算：[a-(1/a)]/a^2-2a+1/a a(a-1)(a-2)(a-3)(a-4)因式分解【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ]