设{an}是等差数列,{bn}是各项都为正数的等比数列且a1=b1=1,a3+b5=21,a5+b3=13.求(1)[an},{bn}的通项公式,(2){an/bn}的前n项和Sn.后面相减看不懂啊
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![设{an}是等差数列,{bn}是各项都为正数的等比数列且a1=b1=1,a3+b5=21,a5+b3=13.求(1)[an},{bn}的通项公式,(2){an/bn}的前n项和Sn.后面相减看不懂啊](/uploads/image/z/1761505-25-5.jpg?t=%E8%AE%BE%7Ban%7D%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%7Bbn%7D%E6%98%AF%E5%90%84%E9%A1%B9%E9%83%BD%E4%B8%BA%E6%AD%A3%E6%95%B0%E7%9A%84%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%E4%B8%94a1%3Db1%3D1%2Ca3%2Bb5%3D21%2Ca5%2Bb3%3D13.%E6%B1%82%281%29%5Ban%7D%2C%7Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%2C%282%29%7Ban%2Fbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn.%E5%90%8E%E9%9D%A2%E7%9B%B8%E5%87%8F%E7%9C%8B%E4%B8%8D%E6%87%82%E5%95%8A)
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